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Boolean algebra: DeMorgan’s theorem
DeMorgan’s theorem
A + B
=
A
∙
B
A + B + C + … + Z
=
A
∙
B
∙
C
∙ … ∙
Z
A ∙ B
=
A
+
B
A ∙ B ∙ C ∙ … ∙ Z
=
A
+
B
+
C
+ … +
Z
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